Question

I’m in hurry please

Question2 0.75 pts It is known that R1-R2-R3-1 ㏀、С-1500 mF and Vs 1 2 V for the RC circuit in Figure 2.2. where the switch was open for a long time and is closed at t -O sec 1 R1V2 Vc Ic Switch Vs 12 R2 Figure 2.2 The voltage V2tt) at t -1.0 sec is most approximate to 8.32 V 1.64 V 6.74 V 3.37 V

Answer 1

Voltage across capacitor v_c(t) is given by v_c(t) = v_final - (v_final - v_initial) e^-t/Rc V_Final = final value of voltage across capacitor v_initial = initial value of voltage across capacitor here switch is open circuit so final voltage across capacitor is the voltage across R_2 (when capacitor is open I-c = 0) implies v_final (R_2/R-1 + R_2) 12 = (1 k/1 k + 1 k) 12 \r\n = 1/2 times 12 v_final = 6 v here R = (R_1// R_2) + R_3 = (R_1 R_2/R_1 + R_2) + R_3 = (1 k + 1k/1 k + 1 k) + (1 k) = (1 k + 1 k/2 k) + 1 k = (1/2) k + (1 k) = (0.5 k) + (1 k) implies R = 1. 5 k c = 1/1500 m f RC = 1.5 k times 1/1500 m F R C = 1. 5 k times 1/1500 m = 1500/1500 m RC = 10^-3