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Let us verify the Mean Value Theorem with the function f(x) = VE on the interval (2,8). Solution. We have f is continuous on

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We have a f(x) = e = x2 _Clearly, f(x) is continuas on [2,87 and f(x) is differentiable on (28) . Hence, au the conditions of- * rc = 3 = e = g = 4.5 E (2,82 Hence, the only value of a that the Mean Value Theoreti és 4.5. satisfies

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