Question

n order to conduct a hypothesis test for the population proportion, you sample 480 observations that result in 264 successes. (You may find it useful to reference the appropriate table: z table or t table) Ho: pz 0.60 HA: p0.60 a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic 2.24 a-2. Find the p-value. p-vale 0.10 p-value<0.01 0.01 s p-value< 0.025 0.025 s p-value<0.05 0.05 s p-value0.10 a-3. At the 0.05 significance level, What is the conclusion? OReject Ho since the p-value is greater than significance level Reject Ho since the p-value is smaller than significance level Do not reject Ho since the p-value is greater than significance level. Do not reject Ho since the p-value is smaller than significance level. a-4. Interpret the results at α-0.05 We conclude that the population mean is less than 0.6 We cannot conclude that the population mean is less than 0.6. We conclude that the population proportion is less than 0.6 We cannot conclude that the population proportion is less than 0.6

Answer 1

null Hypothesis alternate Hypothesis: Ho: 0.600 Ha 0.600 for 0.05 level with left tailed test, critical value of z= Decision rule 1.645 reject Ho if test statisticz < -1.645 sample success 264 sample size 480.0 std error -Se (p*(1-p)/n) 0.0224 sample proportion p 0.5500 test stat = z ( p-p)/Se- 2.24

a-1)

test statitstic =-2.24

a-2)

0.01 < p value <0.025

a-3)

reject Ho since p value is less than

a-4)

we conclude that ..re less than 0.6

b-1)

test statitstic =-2.24

b-2)

0.025 < p value <0.05

b-3)

reject Ho since p value is less than

b-4) e conclude that ..differs from 0.60