Question

2ί, 4 Ω 3Ω a 6 Ω 2.5A is Is3Ω b Determine/draw the Norton equivalent circuit to terminals ab

Answer 1

- 3 VA + 2 VA +LOVA 30 15VA = 30 2=مد To find 'w 22 Yur для 32 AAA 62 G TA 3° Apply kul to right loop. -vt (361) + 3ix & ix= VA = 를 사 3 3 5v 3+3x2 3 so, RNS IRN=52 1 IN VA zix 42 B 32 A for Isor this cixcurt we have staromodes VAZN bu şi 2.5A i) i termodadanalysis modabra super mesh mesh 2 (1) -iz use an super mesh. 2.5 ED = +61, +2ix + 4 1₂ +3 (12-13) = 0 + ulson ix= 12-13

toil+2 (12-13) + 412+ 3(12-13) = O => +61 +giz-513 = SO ii in loop (3 31 3+3 (13-12)=0 » -3i2 +6i3=0 ID Ti = 4A, 12=-4A, i3=5A In the circuit iz = IN=5A RN=502 IN=5A

Sol ก: Given circuit zix 312 Дл- a 6023 2.5A We have to calculate Nortan's equivalent circuit i.ee IN= Norton's equivalent current through after shorting ab. equivalent resistance accres ab. ab RN = RN Replace independent current source 2.5A by open circuit but we can not do anything with dependent sources in the circuit To calculate RN put a current source of 1 A (ideal) and volteye aceness this current source is v. RNE V ✓ = so, = vr - zix 42 VA A BUL Apps KCL @ VA (node). + buz VA +2ix lo 1 VA 3 =1 302} lix + ТА o and ix = VA 3 put in VA = 1 VA 10 VA 3 5 3 VA 3 =1 10 15