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A. Answer the following questions below. You may use LT (for is less than), GT (for is greater than), EQ (for is equal to), MI (for more information is required), or true/false. 1. If 0.10 M Na2S is added to 1.00 L of a saturated solution of ZnS, the molar solubility of ZnS does not change. 2. Addition of NaCt will increase the solubility of ZnS. 3. Addition of Zn2+ results in the precipitation of ZnS. 4. Ksp has a fixed numerical value at a given temperature 5. The molar solubility of AgCt increases with an increase in temperature. u Ju Explain why you choose the answer you did .

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Answer #1

1. False.

Explanation: Due to the common ion effect of S2- ion, the solubility of ZnS will be further suppressed.

2. True.

Explanation: 2NaCl + ZnS \rightarrow Na2S + ZnCl2

3. True

Explanation: Due to the common ion effect of Zn2+ ion, the solubility of ZnS will be further suppressed, i.e. ZnS will be precipitated.

4. True.

Explanation: Ksp is the constant value for a sparingly soluble salt at a given temperature.

5. True.

Explanation: As the temperature, increases, the solubility product (Ksp) increases, as a result, the molar solubility increases.

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