Please answer all four of
these questions and explain WHY. I don't understand any of this.
Thank you!
Homework Answers
Ans :
1) the rate of reverse reaction is zero
When the reaction has just started , there are only reactants in the system and no products , so the reaction will only move forward. SO3 hasn't formed yet , so the rate of reverse reaction is zero.
2) Greater than zero, but less than the rate of forward reaction
Now when some of SO3 has been formed in the system ,the reaction will also proceed in reverse direction , but with the same rate as forward but less because the system hasn't reached equillibrium yet.
3) Greater than zero , equal to the rate of forward reaction
At equillibrium the rate of forward reaction becomes equal to the reverse reaction.
4) Some , but less than 1.55 moles
Here SO2 amount is less so it is limiting. The amount of SO3 will be formed but less than SO3 , as at the equillibrium there is still some SO2 present in the system.
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