Since drop is suspended, the force of gravity ( downward) is balanced by the electrostatic force ( upward implies the drop has negative charge)
So,
0= mg-|q|E
m = (4/3)πa3 = (4/3)(0.859)(3.14)(1.70×10-4)3= 17.67×10-9 kg
mg = qE
(17.67×10-9)9.81= q(0.318×105)
q = -5.45×10-13C
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