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In Millikan's oil drop experiment, a drop of radius r = 1.69 µm (1µm = 10-6m)...

In Millikan's oil drop experiment, a drop of radius r = 1.69 µm (1µm = 10-6m) and density 867 kg/m3 is suspended (against gravity) in a uniform electric field (Fe cancels Fg) when the drop has 4 excess electrons. What is the magnitude of the electric field (in N/C)? (Note that you can enter the full number or use the format 9.99E9 where "E9" represents 109). Enter only the numerical part of the answer (not the units).

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Answer #1

Since the drop is in equilibrium frut=0 - Electrostatic fore mgaiq E) - m=fu (Density & volums) ma 867 X LT173 ma 8670 4 x 3.

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