Question

Fill in the missing values. Show all your work AND one fully labeled impedance graph as a general template. Round your answers to the nearest ohm PART A COMPLETE THE TABLE R, 12 X, 2 X, X,122 ,12 00°00'00.00" 1 27 54 1 90 281°13'44.01" 35 350 65 3 500 810 1500 T L 3900 2400 2650 47°2922.39" 44°36'00.00" 72°00'00.00" 28°00'00.00" 6 7 8 115 T 4.22 - - 1 975 - - - 5140 312 5.75 1776 5560 256 10 125 Positive angle PART B 1. A circuit has a resistance of 1252, an impedance of 2562, an inductive reactance of 31212 and a positive phase angle. Find the capacitive reactance and the phase angle. 2. Add the following vectors. 736Z15.8° 586269.2° 826Z81.5° 3. Resolve into x and y components. 232-179 4. Determine the polar coordinates of the following points. i) (-10,-7) ii) (5.3, -10.8) 5. Solve the following. i) (2.25 + 15.43)-(-3.79 - 12.15) ii) (0.178 - 11.275).(3.216 + 30.982) (4+ j7) (2-15)

Answer 1

© Given R=1252 z =25602 x2 = 31232 Xc=? we know - z= J &t (fe- xey 256 = |(125) 4 (312–8) 65 55 – 0s) - 62 - xy 312 -*c = 223:4 | Xc = 88:62 phase angle P = tan (**) = ran (925) [ 0 = 60.77 ® 736 115.18 + 586.692 +826 185 B = 1878.26 56.40. © 251-179 we know a= rcoso y = rsino where r=23 O = -1799 X = -23 y = -0.4 % 4 Giron Go? 8= Satyr oz tari (8/2) Now (x2122 -143" <LD =126-6336 50 6.04+ 7.58 i @ 1-824 – 3-4 2.3 (ii-0.93+ 1.173 please make a comment if you have any doubts. thank you