Consider the reaction represented by the equation:
Fe3+ (aq) + SCN- (aq) FeSCN2+ (aq)
What is the equilibrium concentration of FeSCN2+ (aq) if a solution is prepared that is initially 6.00 M Fe3+ (aq) and 6.00 M SCN− (aq)? if k was determined to be 0.333
Consider the reaction represented by the equation: Fe3+ (aq) + SCN- (aq) FeSCN2+ (aq) What is...
1) Consider the following equilibrium: Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq) Initial concentrations: [Fe3+] = 0.590; [SCN-] = 1.239; [FeSCN2+] = 0 The equilibrium concentration of [FeSCN2+]eq = 0.454 M. What is the numerical value of KC for this equilibrium? KC = __________________ 2) Consider the following equilibrium: Fe3+(aq) + SCN-(aq) ⇌ FeSCN2+(aq) Initial concentrations: [Fe3+] = 0.370; [SCN-] = 0.777; [FeSCN2+] = 0 The equilibrium concentration of [FeSCN2+]eq = 0.285 M. What is the equilibrium concentration of Fe3+? [Fe3+]eq =...
Consider the following reaction: Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq) A solution is made containing an initial [Fe3+] of 1.2×10−3 M and an initial [SCN−] of 8.2×10−4 M . At equilibrium, [FeSCN2+]= 1.8×10−4 M . Calculate the value of the equilibrium constant (Kc)(Kc). Express your answer using two significant figures.
* PLEASE WRITE OUT ANSWER STEP BY STEP! CONSIDER THE FOLLOWING REACTION: Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq) A solution is made containing an initial [Fe3+] of 1.2×10−3 M and an initial [SCN−] of 8.2×10−4 M. At equilibrium, [FeSCN2+] = 1.6×10−4 M . PART A: Calculate the value of the equilibrium constant (Kc): [Express your answer using two significant figures] KC = _____________________________
At a certain temperature, K = 8.60 x 10^-4. for the reaction FeSCN2+(aq) ⇄ Fe3+(aq) + SCN-(aq) Calculate the concentrations of Fe3+, SCN-, and FeSCN2+ in a solution that is initially 2.0 M FeSCN2+.
Calculate the equilibrium constant for the reaction Fe3+ (aq0 + SCN (aq)→ FeSCN2+ (aq) given that the mixture of 5 ml of.00359 M SCN- and 5 ML of .00200 M Fe3+ solutions yield 1.68 x 10A- 4 M FeSCN2+ at a given temperature. a.) 23 . B.) 93 d. 8.06 x 10A-3 c.) 124
2. The reaction Fe3+ (aq) + SCN (aq) → FeSCN2+ (aq) produces a dark red color resulting from the formation of FeSCN2+. a. How does the color change if you add more SCN to a solution at equilibrium? (lighter or darker) b. How does the color change if you remove Fe3+ by reacting it with fluoride ions? c. If a reaction proceeds forward when you heat it, and reverse when you cool it, the reaction is [endothermic exothermic).
Equilibria can be treated mathematically with the equilibrium constant, K. For the reaction Fe3+ + SCN − equilibrium reaction arrow FeSCN2+, the equilibrium constant expression is [FeSCN2+ ] K = [Fe3+ ] · [SCN − ] where, for example, [Fe3+ ] is the molar concentration (mol Fe3+ / L solution) present in an equilibrium mixture. At some temperature, a chemist found the following equilibrium concentrations. [Fe3+ ] = 8.17 ✕ 10−3 M, [SCN − ] = 8.60 ✕ 10−3 M,...
Balance the equations. Fe3+(aq) + SCN–(aq) <--> FeSCN2+ Ag+(aq) + SCN–(aq) <--> Ag(SCN)4 ^3- FeSCN2+(aq) + Ag+(aq) <--> Ag(SCN)43- + Fe3+(aq) Use Le Chatelier’s principle to explain the different colors and how they relate to the disturbance of the equilibrium.
When solutions containing Fe3+(aq) ions and SCN−(aq) ions are mixed together, the following equilibrium is established: Fe3+(aq)+SCN−(aq)⇌FeSCN2+(aq) At equilibrium at some temperature, in 3.0 liters of total solution, there are 0.653 moles of FeSCN2+(aq), 0.0385 moles of Fe3+(aq) and 0.0465 moles of SCN−(aq) . What is K?
My question is #2 for the reaction Fe3+ (aq) + SCN- (aq) FeSCN2+ (aq). The goal is to predict the color change (darker or lighter) for test tubes 2-8. I have attached the supplemental sheets given to help with the problem. The test tubes 2-8 are being manipulated either by temperature or things being added which can be seen by one of the pictures. 2. For reaction "UCTIONS are increased by the same amount. Fe3+ (aq) + SCN (aq) $...