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A 2.5-lb collar is attached to a spring and slides without friction along a circular rod in a vertical plane. The spring has

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we ure energy conservation 3 A 4 energy at @ = energy att B spring Ni k x? > 5-4 c length at ce 7-3 7-3. hinch extension= 4-وفى Now apply E. = E PEAT FEA+ SPA +55 こ PEx + FBC (PEC-PEX). 2 2 į mu? (2.5x32:247) = KEA+SP mg (R) +0.06.944 1 (C205) v? +0o SP Sposo OL Sp- Spring force こ r os Tan (12/4) 23.1985 N=mus (spcose) (20x 1 ) cos 23.148. (+) N = 160 12-14531 N = 159:

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