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Question 3: a) Calculate the no-load voltage v, for the voltage divider circuit shown. b) Calculate...
0 40 V The no-load voltage across R2 in the voltage-divider circuit shown is shown is vo.no_load 8 V The smallest load resistor that is ever connected to the divider is RL,smallest 3.6 k Ω (kilo Ohm) When the voltage divider is loaded by RLsmallest, VO is not to drop below 7.5 V A) Assume the power ratings of commercially available resistors are 1/16, 1/8, 1/4, 1, and 2 W What power rating would you specify? PR1,rating Watt PR2.rating =...
Problem #4 In the voltage-divider circuit shown in Figure, the no-load value of y, is 4 V. When the load resistance R, is attached across the terminals a and b, v, drops to 3V. Find R 40.2 w 20 V 20v & R2 vo {RL
2. Voltage divider for a group of resistors Ri Figure 2 The voltage divider circuit For the circuit shown above, derive the espression for the output voltage V, as a function of the input voltage and the resistances (V, Ri,and R2)
The circuit diagrams display a device called a voltage divider. Long Resistor Slide Voltage Divider 2 V. m ( R, VOUT = R + Suppose a voltage divider is constructed from two fixed resistors. If VIN = 30 V, R1 = 126.2, what should the value of R2 be so that Vout is 10 V? R2 =
In the voltage-divider circuit shown in the figure, the no-load value of vo is 5 V When the load resistance RI is attached across the terminals a and b, vo drops to 3 V.(Figure 1) PartA Find RL Express your answer with the appropriate units RI-7.28 Submit Previous Answers Request Answer Incorrect, Try Again: One attempt remaining Provide Feedback igure 1 of 1 40Ω 20 V R2 vo
(a) A voltage divider bypassed common-source (CS) FET amplifier biasing circuit with load R, is commonly used in electronic circuit. (1) Design the circuit of a voltage divider bypassed common-source FET amplifier biasing circuit with load Ru. [4 marks) (ii) By referring to Q4(a)(i), design a bypassed common-source FET amplifier with biasing voltage-divider to meet the given specifications below: Supply voltage, Vcc = 12 V; Voltage gain, Ay = -10; Output load Ru = 10 kV2; input impedance Zi =...
Question #1 (20 pts.) (Begin your solution on a new page) a-(15 pts) The voltage divider shown below is comprised of a stable 45.00 volt source and three, 1/4 watt, 1 KQ resistors with a tolerance of 5%. What is the nominal output voltage, Vout, as well as the range of voltages that you might expect? b-c4pts) Assuming nominal values, what is the total power dissipated in the circuit? C- (1 pt) Are these resistors an appropriate choice for this...
Question 8 5 pts The circuit shown in the figure below contains three resistors (R1, R2, and Rs) and three batteries (VA. Vg, and V). The resistor values are: R2-2 Ohms, R2-R3-6 Ohms, and the battery voltages are VA-25 V. V8-15V, and Vc-20 V. When the circuit is connected, what will be the power dissipated by R2? VC R 3 VA VB R2 R₃ 10W 2.0 W oooo 5.0 W 6.0 W 7.5 W Question 9 5 pts The circuit...
How do you calculate the load and bleeder currents in a voltage divider? Vs = 10V. R1 & R2 both 10,000 ohms each. 3. Connect a 100 kS2 load to the circuit. Apply power, and measu age (½). Use la to calculate: . The load and bleeder currents.
Fig. 1. Logic circuit for Question 1 2. The 60 W light bulb shown in Fig. 2 is rated at 120 volts. Calculate the required supply voltage V, to make the light bulb operate at the rated conditions. (2 pts) 50 22 Bulb 3 802 Fig.2. Circuit for Question 2 (3 pts) 3. For the circuit shown in Fig. 3, using KVL & KCL: a. Determine the currents i1, 12 & 13 b. The voltage across the resistor R1, R2...