Here ,
for the value of R2
without load
5 = R2 * 20/(R2 + 40)
R2 = 13.33 Ohm
Now, when load is connected
let the net resistance is R
3 = R * 20/(40 + R)
R = 7.06 Ohm
Now, for RL
1/7.06 = 1/RL + 1/13.33
solving for RL
RL = 15 Ohm
the resitance RL is 15 Ohm
In the voltage-divider circuit shown in the figure, the no-load value of vo is 5 V...
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