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A 2.00 m -diameter vat of liquid is 2.20 m deep. The pressure at the bottom of the vat is 1.50 atm . You may want to review (

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Answer #1

Pressure at depth H is given by

P = P_0 + \rho g H

pgH = P - PO = (1.5-1) ×1.013 ×10^{5}

Putting , g= 9.8

pH = 5168

Mass of liquid is given by

m = pt

Where, V is volume

m = (HA)

A is area

m = pH (rd/4)

= 5168×(12/4)

= 5168× π

= 16236 kg

In three significant figure

m = 16200 kg

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