A 6.5 L sample of nitrogen at 25◦C and 0.76 atm is allowed to expand to 13.0 L. The temperature remains constant. What is the final pressure?
1.) 0.063 atm
2.) 0.75 atm
3.) 0.38 atm
4.) 3.0 atm
5.) 0.12 atm
From Boyle's law,
At constant T,
P1V1=P2V2
P1=0.76atm
V1=6.5L
V2=13L
P2=?
P1V1=P2V2
P2=P1V1/V2
P2=0.76*6.5/13
P2=0.38atm
So the final.pressure = 0.38atm
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