Question

30. Let us consider you have given your data to a computer to analyze, and it tells you the p-value = 0.0004. If your significance level (alpha) is 0.05, then you would a. fail to reject the null hypothesis b. reject the alternative hypothesis C. reject the null hypothesis d. consider the computer has given you an incorrect value 31. With small degrees of freedom, the t-distribution is not quite Normal, but with degrees of freedom the t-distribution will more closely approximate a Normal distribution a. increasing b. decreasing C. zero d. none of the above 32. To create a confidence interval for comparison of means, we need a margin of error just like in proportions tests, but in this case the margin of error is t* SE, where SE is the standard error and t* is a. a t-value based on the difference of the expected versus actual counts b. an estimate of the mean of the sample c. the proportion of successes in the sample d. a t critical value from the table based on the confidence level and th freedom of the sample

Answer 1

30 ) Answer is c.

Let us consider you have given your data to a computer to analyze, and it tell you the p value = 0.0004. If your significance level is 0.05 , then you would Reject the null hypothesis.

( Decision - Reject H0 if p value < significance level )

31) Answer is a.

With small degrees of freedom , the t distribution is not quite normal , but with increasing Degrees of freedom the t distribution will more closely approximate a normal distribution.

( As the observation increases then it will follows normal distribution i.e. approximately 30 observation )

32) Answer is d.

To create a conference interval for comparison of means , we need margin of error just like in proportion test but in this case marginsof error is t*SE , where SE is Standard error and t* is a t critical value from the table based on the confidence level and degrees of freedom of the sample.  

( t is nothing but the critical value of t using t table )  

PL??