J = 7.43 * 10^6 A/m^2
A = 1.99 * 10^-6 m^2
We know,
J = I/A
I = J*A
I = 7.43 * 10^6 A/m^2 * 1.99 * 10^-6 m^2
I = 14.78 A
I = Q/t
Charge of 1 electron = 1.6 * 10^-19 C
Charge of 5.87 * 10^20 electrons, = 1.6 * 10^-19 * 5.87 * 10^20 =
93.92 C
t = Q/I
t = 93.92/14.78
t = 6.35 s
Time, t = 6.35 s
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Please answer this question:
An aluminum wire having a cross-sectional area of 2.10 ✕
10−6 m2 carries a current of 6.00 A. The
density of aluminum is 2.70 g/cm3. Assume each aluminum
atom supplies one conduction electron per atom. Find the drift
speed of the electrons in the wire.
Please answer correctly!!!! Thank you so much in advance!
Safari File Edit View History Bookmarks Window Help 恸 令49%DEE1 Mon 3:12:37 PM 6.585*10*-5 X Your response is off by a multiple...
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