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9. Find the probability that in a sample of size 15 from a normal distribution with mean=500 and sd=100 the sample average is

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Given that, n = 15 M = 500 sampl mean size - MX = l = 500 So, x100 - 25:82 PCX 2550) = P(x-u > 550-500) = 1-P (X-4x (550-500)

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