Question

i am stuck can someone help me answer these please

0.2.9 Question Help 0 Find the indicated 10 score. The graph to the right depicts 10 scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. Click to view page 1 of the table. Click to view page 2 of the table. 0.99 0 The indicated IQ score, x, is (Round to one decimal place as needed.)

Answer 1

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Here, Let X - Normal(100.00, 15.0002) Now, To find x such that P(X < x) = 0.99 X – 100.000 → PC 15.000 X – 100.000 15.000 = 0.99 X – 100.000 = P(Z < 0.99 15.000 — 100.000 004 -) = 0.99 15.000 X – 100.000 0-4(0.99) = 2.326348 15.000 > x = 100.000 + (2.326348 * 15.000) + x = 134.895218 134.90

Let p denotes the population proportion. Let o denotes the sample proportion and n denotes the sample size. Here, P = 0.850, n = 400, standard error = 0.850 * (1 – 0.850) 400 = 0.017854 0.0179 At 99 percent confidence level, Margin of error is p* (1 - ) ME= * 21-0.99 = 0.850 * (1 – 0.850) 400 * 20.005 0.850 * (1 – 0.850) 400 * 2.575829 = 0.045988 ~ 0.046 n a 99 percent confidence interval for the population proportion p is p = (1-0) = * 2 1-0.99 n = 0.8500 + 0.850 * (1) 0.850) 400 * 20.005 = 0.8500 + 0.850 * (1 – 0.850) * 2.575829 400 = 0.8500 + 0.045988 (0.804012, 0.895988) ~(0.804,0.896)

3.

Here, 21 = 71.000, $1 = 3.9600, n1 = 14,02 = 67.000, S2 = 2.1700, n2 = 11 and associated degrees of freedom + nu df= = 21 + ni n2-1 The Standard error is 3.962 SEN + + 2.172 11 1.244 ni n2 14 The critical value is tcritical =t1-09 ,21 t0.05,21 = 1.720743 1.721 The margin of error is ME=t1-0.9 + t0.050,21 3.962 V 14 + 2.172 11 = 1.721 * V 3.962 V 14 2.172 11 = 2.141061 2.141 ni n2 a 90 percent confidence interval for the differnce in population means (ui - U2 ) is si = 21 - 22 + + *ti 0.900 n2 2,21 ni =či - 12 + ME (71.000 - 67.000) = 2.141061 = 4.000 + 2.141061 = (1.858939, 6.141061) (2,6)