Question

can someone help me answer these please! i am stuck and these are the only questions i do not get it would be a huge help please

Question Help Assume that thermometer readings are normally distributed with a mean of oC and a standard deviation of 1.00°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Calsius degrees.) Between 0.75 and 1.75 Click to view page 1 of the table Click to view page 2 of the table. Draw a sketch. Choose the correct graph below. Library ОА OB Oc Cancel h Contents 7-075 e Resources 20.75 2075 1.75 Success The probability of getting a reading between 0.75°C and 1.75* CI (Round to four decimal places as needed.) Success se Options Tools

Answer 1

Thermometer readings are Normally distributed with a mean, M20°C. and a standard deviation of = 1:00'e NON, we have to sketch and find prob. of the seading. Reading is between 0.75 and 175 27 BINAR 1.75 0.750 1°75- s oć 0.78 correct option is B Now, P(0.75 < X < 1'75) z P/x41°75) - P(x40-50 P(X-MS ==0)-1484 P(Z 5 1.75) - P(Z30-715) 0.9599 - 6.7734 : 0.1865 i =

P2 on 12' 2 Bone deusity test scones au Norma rally distributed with mean, M20 ånd a standard deviation of or1 Now. We have to draw a graph Now, 12th Rercutile means that value of data under which 127. data lies and above wlich 88% data lies. th PIR Correct option is ce). NOW, by definition of Percutite, P(x ca) 0.12

on PC-X-4 P sa de 20:12 어 20:12. OM P(Z < Za Now, according tablesplz < -1'175) =0:12. a) 2 to standard normal So, za 2:1 175. or a-m 2 - 1.175 or a - 0 2-1.175 1 OM, az'-1.175 1.18 So, Bone density score is -1.18 3. The adulto have I B Scores that are Normally distributed with mean, Ma 185 anda Standard deviation,' 220-

We have to find the probability that, adult has an Is score between 92 and 1180 ie PL924 X 118 ? PL 24 118)- P(x +92) 2 P(X+F; 19.105) PLX-H £ 92-105) 2 PLZ€0.65) – P[24-0.65) 0.7422 0.2578 = 10^4.844 2