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Homework: Section 6.1 Sav Score: 0 of 1 pt 10 of 21 (9 complete) HW Score: 42.86%, 9 of 21 6.1.25 Question Help Assume that t
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Answer:

1)

1050 11.25

2)

We want to find area between z= 0.50 and z=1.25

We want to find P(0.50 < z < 1.25)

P(0.50 < z < 1.25) = P(z < 1.25) - P(z < 0.50)

using normal z table we get

P(z < 1.25) = 0.8944

P(z < 0.50) = 0.6915

P(0.50 < z < 1.25) = 0.8944 - 0.6915

Answer= 0.2029

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