Question

5. 1 kN/m A Draw the shear force and the bending moment diagrams along the beam. B 10 m 7 m 7 m

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Answer 1

Ans :

Ans: free body dia of the beam. 10KN B А D V RcH * 5m 45m → 14 m. RB. Rear are - for hinged or rigid support there 2 components of forces jie vertical and horizontal for rolling support there vertical component of force . is only tae * RA & RB. for finding E Fx=0 RCHE ( Horizontal) * {fy (consider q=tve, do=ave RB + Rev = 10 KN finding moment about pt.C * E c EMC EMCE Here we will we will consider 6) = tve & (6) = -ve

E Mezo RB X 14 1oxig RB 13.57 KN in from ean o Rova 3-57 K N X Here -re sign indicates that vertical component of force acting at c is actually acting downwards f Rc = RCH + Rcve Rov i-/Rcs RCS - 3.57 KN

Here R_c = 3.57 KN acting downwards (-ve)

* are 93 * for eg arour shear force día. calculations There different methods of solving we will make 2 compartments around force left and right and for calculations we will consider always Whatever forces that gre left side of that particular compartment force of suppose io kips we will make 2 compartments und it as shown. jokios th for calculations we always consider forces left to that particular compartment jae for left left compartment there is no force to the left side SFL = for left side of right compartment there is there is lokios force SFR = lokips =-ve) R SOS O

** SFD : calculation : cr=tve, v=ove) 09907 oil thodunt SFDL= SFDR = 10 KN SFBI SFBR . E-10 KN -10t 13.57 KN 3.57 kr von - - SF.cl SFCR = 3.57 = 73.5 7 -3.57 ** B MD calculations: (Take g=tve dod Q =-ve) There is no such making of compartments BMD Calculations. At the free end of the beam Bending moment io always zero ** B Mc co we will take moment about by considering only forces that are left of the pt. of focus, ** 8*8 = - 10 x 5 - 50 kNim

9 = 1 RA Rp Н. A B TH 10 (m) 14 (m) t + 1 sec. (X1) 2 sec. (X2) 3.57 0 Qy -10 -50 Mx 0

Here 1st image is of beam

2nd image or say graph is of SFD

And 3rd graph is showing BMD

Moment is taken as positive ,when the tension is at the bottom of the beam . Hence bending moment is drawn above the axis in BMD.