Question

D Question 25 Calculate the pH of a 0.10 M CH3NH,Cl solution. Ky(CH NH) - 4.4x104 5.82 943 Сосоо 4.36 8.18 Question 26 5 pts When a strong acid is added to a strong base in a titration, what is expected at the equivalence point? A acidic solution from the conjugate acid of the strong base A neutral solution with a pH - 7 A acidic solution from the strong acid A basic solution from the strong base A basic solution from the conjugate base of the strong acid

Answer 1

23. CHy MH, a + H2O = CH, MHz + 120 + HUL weak base strong acid. An aqueous solution of CH3 NH, ce would be a 3olution of weak base and strong acid, because on hydrolysis. it will form a weak base and strong acid. 1. pto 1 pkw - loko - doge. Нали pl.w . ч. koo 4,4x 10-4. ::pkbo-log (4.4x10-4), se sio 0.10 M. 3.36. on

:. pH. $x14 - $* 3-36 - ilog 10.10). 7-1168 - (-0.5). TpH 5.82. Answer 26. when strong acid is added to strong base at the equivalence point it will form a salt, which will not hydrolyse back to acid and base. Hee thaOH Nace H.O. - acid base salt & teater, Dhers at equivalence point. the solution would be. neutral with phot. Amb A neutral solution, with a pHa it. - 27. The molecule which has a less than octate at. the valance shell is deficient of electron. The molecule will these fose acts as Leevis acid. No. of ers in the valance shell of 17 , 3 valance e from B+ 3 3. from fluorim 6. so BE a haso less than light electrom as in their valan u shell. so acts as lewis aeid. AmE BF3.