Homework Answers
20)
a)
pH = 1/2 (pKa - log C)
= 1/2 (4.74 - log 0.10)
pH = 2.87
b)
mmoles of NaOH = 1.5 x 0.1 = 0.15
mmoles of acid = 25 x 0.1 = 2.5
HA + NaOH -------------> A- + H2O
2.5 0.15 0 0
2.35 0 0.15
pH = pKa + log [A- / HA]
= 4.74 + log [0.15 / 2.35]
pH = 3.54
c)
volume of NaOH needed = 25 mL
d)
salt present = CH3COONa
sodium acetate salt present. this is basic .
e)
salt concentration = 25 x 0.1 / 50 = 0.05 M
pH = 7 + 1/2 (pKa + log C)
= 7 + 1/2 (4.74 + log 0.05)
pH = 8.72
f)
[H+] = 0.0167
pH = 1.78
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