HC2H3O2 is a weak acid and NaOH is a strong base , there will be excess OH^- at equivalence point due to strong base (NaOH) and hence solution will be basic at equivalence point.
Option (a) Basic because of excess OH^- , is the correct answer.
***A 50 mL solution of 0.10 M HC2H2O2 (aq) (K = 1.8 x 10-5) is titrated...
***A 50 mL solution of 0.10 M HC2H2O2 (aq) (K4 = 1.8 x 10-5) is titrated with 0.20 M NaOH (aq)*** What is the pH after the addition of 5.0 mL of NaOH(aq)? O 8.98 2.87 O 3.58 0 4.74 4.14
Question 25 ***A 50 mL solution of 0.10 M HC2H2O2(aq) (Kg = 1.8 x 10-5) is titrated with 0.20 M NaOH (aq)** What is the pH after the addition of 5.0 mL of NaOH (aq)? 4.14 o 4.74 2.87 8.98 O 3.58 Previous
***A 50 mL solution of 0.10 M HC2H302 (aq) (K2 = 1.8 x 10-S) is titrated with 0.20 M NaOH (aq). ** What is the pH when 30 mL of NaOH(aq) is added? 8.98 o 12.10 - 1.90 O 11.23 o 12.90
For the following titration, determine whether the solution at the equivalence point is acidic, basic or neutral and why: KOH is titrated with HI(aq) basic because of hydrolysis of K+ basic because of hydrolysis of KOH acidic because of hydrolysis of OH- acidic because of hydrolysis of HI neutral salt of strong acid and strong base
Consider a titration of 250 mL 0.15 M acetic acid (Ka = 1.8 x10-5) with 0.10 M KOH. What is the pH of the acetic acid solution (ie: before the titration has begun?) What is the pH after adding 25 mL of 0.10 M KOH? What is the volume of base needed to reach the equivalence point? Is the pH at equivalence point acidic, basic, or exactly neutral? What is the pH after 500 mL of KOH has been added?
D Question 25 Calculate the pH of a 0.10 M CH3NH,Cl solution. Ky(CH NH) - 4.4x104 5.82 943 Сосоо 4.36 8.18 Question 26 5 pts When a strong acid is added to a strong base in a titration, what is expected at the equivalence point? A acidic solution from the conjugate acid of the strong base A neutral solution with a pH - 7 A acidic solution from the strong acid A basic solution from the strong base A basic...
7. A sample of 0.10 M C6H5COOH(aq) (benzoic acid) solution is titrated with 0.10 M NaOH(aq) solution. What is the pH of the solution at the equivalence point? Ka(C6H5COOH) = 6.46 x 10-5 8. A sample of 0.10 M C6H5CH2NH2(aq) (benzylamine) solution is titrated with 0.10 M HBr(aq) solution. What is the pH of the solution at the equivalence point? Kb(C6H5CH2NH2) = 2.24 x 10-5
Part B: A 30.0-mL volume
of 0.50 M CH3COOH (Ka=1.8×10?5) was titrated with 0.50 M NaOH.
Calculate the pH after addition of 30.0 mL of NaOH at 25 ?C.
Express the pH numerically.
MasteringChemistry: ASSIGNMENT #6 (Chapter 16)-Google Chrome https://session.masteringchemistry.com/myct/itemView?assignmentProblem ID=59386 148 CHEM 101 (M03) Help | Close NMENT #6 Titration of Weak Acid with Strong Base Resources Y previous | 19 of 25 | next » ± Titration of Weak Acid with Strong Base A certain weak acid, HA...
A 40.0 mL solution of 30.0 M of succinic acid (aq) is titrated with 0.300 M of KOH. Find the pH of the solution. (pKa=4.2). A) initially B) 1/2 way to the equivalence point C) at the equivalence point D) 1.00 mL past the equivalence post 2) sketch the titration curve that results from above titration. Label A) only a weak base present. B) Buffer. C) Only a weak acid present. D) Strong base in excess. E) pH = pKa
An unknown acid is titrated with a strong base (NaOH) to produce
the above titration curve. Key points on this graph reveal
important information about the substance and the solution created
with it.
What volume of NaOH is needed to reach the equivalence point
(the point where you added equal moles of NaOH to the
acid)? Select one of the following : ["10 mL", "5
mL", "20 mL", "30 mL", "40 mL", "25 mL", "15 mL", "35 mL"]
...