***A 50 mL solution of 0.10 M HC2H302 (aq) (K2 = 1.8 x 10-S) is titrated...

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Answer 1

Answer #1

CH₃COOH cap + oH cap → CH₂ Loo loq) + tho (1) acid = 50 L x Moles of acetic 0.10M 1000 POJlPosols M 2p. = 0.005 mol 1M SEPSE

Answer 2

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