Question 25 ***A 50 mL solution of 0.10 M HC2H2O2(aq) (Kg = 1.8 x 10-5) is...
***A 50 mL solution of 0.10 M HC2H2O2 (aq) (K4 = 1.8 x 10-5) is titrated with 0.20 M NaOH (aq)*** What is the pH after the addition of 5.0 mL of NaOH(aq)? O 8.98 2.87 O 3.58 0 4.74 4.14
***A 50 mL solution of 0.10 M HC2H2O2 (aq) (K = 1.8 x 10-5) is titrated with 0.20 M NaOH (aq). " At the equivalence point is the solution acidic, basic, or neutral and why? o Basic because of excess OH O Basic because of hydrolysis of C2H302 o Neutral salt of strong acid and strong base O Basic because of hydrolysis of HC2H2O2 Acidic because of hydrolysis of Nat
***A 50 mL solution of 0.10 M HC2H302 (aq) (K2 = 1.8 x 10-S) is titrated with 0.20 M NaOH (aq). ** What is the pH when 30 mL of NaOH(aq) is added? 8.98 o 12.10 - 1.90 O 11.23 o 12.90
JUILLS alcalUWCU. FUUWI LLUCOCUIDLUI d luck! Question 21 ***A 50 mL solution of 0.10 MHC2H302 (aq) (K = 1.8 x 10-5) is titrated with 0.20 MNaOH (aq). ** What is the pH when 30 mL of NaOH(aq) is added? O 11.23 O 1.90 O 8.98 12.10 O 12.90 Prevus Quiz saved at 1:55pm
A sample of 0.100 M acetic acid (Kg = 1.8 x 10-5) in 50.0 mL of solution is titrated with standard 0.100 M NaOH. What is the pH in the titration flask after addition of 15.0 mL of NaOH? O a. 11.40 O b. 3.18 O c. 1.88 O d. 4.38 Oe. 4.74
pls show all work. 11,13,14 all all part of the same titration problem! I attempted it several times and am getting very confused WA *** A 50 mL solution of 0.10 M benzoic acid (HC7H502 (aq)) (Ka = 6.5 * 10-5) is titrated with 0.20 M NaOH (aq). With this information, answer the questions (11-14) below.*** SB 11. What is the pH after the addition of 5.0 mL of NaOH (aq)? A) 5.49 B 3.58 C) 4.19 D) 2.59 E)...
25. 50.00 mL of 0.10 M CH3COOH (Ka = 1.8 x 10") is titrated with a 0.10 M KOH solution. After 75.00 mL of the KOH solution is added, the pH in the titration flask will be A) 9.31 B) 9.18 C) 9.52 D) 11.63 E) 12.30
show all work Consider that 20.0 mL of 0.10 M HA (an arbitrary weak acid, Ka= 2.5 × 10−6) is titrated with 0.10 M NaOH solution. The ionization of HA in water occurs as the following. HA (aq) + H2O(l) ⇌ A (aq) + H3O (aq) The neutralization reaction between HA and NaOH can be expresses as the following. HA (aq) + NaOH (aq) NaA (aq) + H2O (l) Answer the following questions. A) What will be the initial...
A 25.0 mL sample of 0.10 M sodium benzoate is titrated with 0.10 M HCl(aq). What is the pH after the addition of 25 mL of HCl(aq)? (K) of CoH;CO2- - 1.6 * 10-10) O pH <7 and > 3 O pH>10 O pH > 7 and <10 O pH=7 O pH< 3
25 mL of 0.10 M acetic acid is titrated with 0.10 M NaOH. What is the pH after 30 ml of NaOH have been added? Ka for acetic acid = 1.8 x 10^-5.