Solution:-
(a) p = (4500C4)*(1/2000)^4*(1999/2000)^4496
= 17063165530125*(1/2000)^4*(1999/2000)^4496
= 0.11256
(b) np = 4500*(1/2000) = 2.25
That is the Poisson parameter For 4 cars
=> (e^(-2.25)*(2.25^4))/4!
= 0.11255
(C) option C. The two probabilites are approximataly the same.
defect An automobile manufacturer finds that 1 in every 2000 automobiles produced has a particular manufacturing...
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