show work for both questions please!! A constant force acts on a 5.0 kg object and...

Question

Question

A constant force acts on a 5.0 kg object and reduces its velocity from 7.0 m/s to 3.0 m/s in a time of 3.0 s. Determine the f

show work for both questions please!!

Answer 1

Answer #1

5) using the equation of linear motion we have

v = u + at

3 = 7 + a * 3

a = -1.33 m/s2

force = mass * acceleration

= ma = 5*1.33 = 6.67 N

6) v^2 - u^2 =2aS

0 - 30^2 = 2*a*70

a = -6.43 m/s2

retarding force = ma = 600*6.43 = 3857.14 N

b) a = ug

6.43 = u*9.8

u = 0.65

so the coefficient of friction is 0.65

Answer 2

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