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Question 6 1 pts 6) An object is placed 9 cm in front of a converging...
An object is placed 7 cm in front of a converging lens. An image forms which...
An object is placed 7 cm in front of a converging lens. An image forms which is inverted and has a magnification of -2. Where should the object be moved such that the image is upright and has a magnification of 4? Answer in cm.
1.) An object is placed in front of a diverging lens with a focal length of...
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length o...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
An object 2.00 cm high is placed 45.3 cm to the left of a converging lens...
An object 2.00 cm high is placed 45.3 cm to the left of a converging lens having a focal length of 40.3 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position cm magnification...
A 2.0 cm tall object is placed 10.0 cm in front of converging lens of focal...
A 2.0 cm tall object is placed 10.0 cm in front of converging lens of focal length 8 cm. What can you say about the image formed by the lens? de the image is real, magnified and inverted the image is virtual, diminished and inverted O the image is virtual, magnified and upright the image is real, magnified and upright the image is real, diminished and inverted
1. An object of 5 cm height is 25 cm to the left of a converging...
1. An object of 5 cm height is 25 cm to the left of a converging lens of focal length f = 20 cm. To the right of the first lens is a diverging lens of focal length f = -10 cm. 0 X (15 pts.) (a) Where should the second lens be placed so that we get a real image 40 cm from the second lens? (10 pts) (b) Find the total magnification of the two lenses, size of...
D Question 15 1 pts A4 mm high object is placed 5 cm in front of...
D Question 15 1 pts A4 mm high object is placed 5 cm in front of a concave mirror with radius of curvature 20 cm. Questions 13-15 refer to this situation. Time Attem 1 Hou The image will be: Virtual and upright Real and inverted Real and upright Virtual and Inverted Question 16 1 pts A4 mm high object is placed 9 cm in front of a convex mirror with radius of curvature 12 cm. Questions 16-18 refer to this...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
An object 1.50 cm high is placed a distance of 31.2 cm in front of a...
An object 1.50 cm high is placed a distance of 31.2 cm in front of a converging MIRROR having focal length 13.5 cm. a) Determine the image distance. b) Determine the magnification of the mirror b) Determine the image characteristics (real/virtual, upright/inverted, size). c) Draw an accurate ray diagram of this situation. d) If the object is moved to a distance of 15.8 cm from the mirror, determine the location of the image. e) At what distance from the mirror...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
A 2.0 cm tall object is placed 10.0 cm in front of converging lens of focal length 8 cm. What can you say about the image formed by the lens? de the image is real, magnified and inverted the image is virtual, diminished and inverted O the image is virtual, magnified and upright the image is real, magnified and upright the image is real, diminished and inverted
1. An object of 5 cm height is 25 cm to the left of a converging lens of focal length f = 20 cm. To the right of the first lens is a diverging lens of focal length f = -10 cm. 0 X (15 pts.) (a) Where should the second lens be placed so that we get a real image 40 cm from the second lens? (10 pts) (b) Find the total magnification of the two lenses, size of...
D Question 15 1 pts A4 mm high object is placed 5 cm in front of a concave mirror with radius of curvature 20 cm. Questions 13-15 refer to this situation. Time Attem 1 Hou The image will be: Virtual and upright Real and inverted Real and upright Virtual and Inverted Question 16 1 pts A4 mm high object is placed 9 cm in front of a convex mirror with radius of curvature 12 cm. Questions 16-18 refer to this...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
An object 1.50 cm high is placed a distance of 31.2 cm in front of a converging MIRROR having focal length 13.5 cm. a) Determine the image distance. b) Determine the magnification of the mirror b) Determine the image characteristics (real/virtual, upright/inverted, size). c) Draw an accurate ray diagram of this situation. d) If the object is moved to a distance of 15.8 cm from the mirror, determine the location of the image. e) At what distance from the mirror...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
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