![3. A research firm found that the amount of money smokers spent on cigarettes follows a normal distribution. The population standard deviation is $5. The research firm took a sample of 49 smokers and found that the sample mean is S20 Develop the 98% confidence interval for the population mean. IIO points] 6. A study of attendance at University of Alabamas basketball games revealed that the distribution of games is normally distributed with a mean of 10,000 and a standard deviation of 2,000. What is the probability that a particular game has an attendance of 13,500 or more? [10 Points](http://img.homeworklib.com/questions/24f5ed20-3f5b-11eb-b4b8-b7a53f9d5038.png?x-oss-process=image/resize,w_560)
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3. A research firm found that the amount of money smokers spent on cigarettes follows a...
Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on...
Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A sample of 100 steady smokers revealed that the sample mean is $20 and the sample standard deviation is $5. What is the probability that a sample of 100 steady smokers spend between $20.80 and $22.00?
C is incorrect. Please show your work. 21. Suppose a research firm conducted a survey to...
C is incorrect. Please show your work.
21. Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A sample of 75 steady smokers revealed that the sample mean is $68. The population standard deviation is $13. What is the probability that a sample of 75 steady smokers spend between $65 and $72? A. 0.9518 B. 0.0028 C. 0.9544 D. 0.9733
A researcher found that a cigarette smoker smokes on average 31 cigarettes a day. She feels...
A researcher found that a cigarette smoker smokes on average 31 cigarettes a day. She feels that this average is too high. She selected a random sample of 15 smokers and found that mean number of cigarettes they smoked per day was 28. The sample standard deviation was 2.4. At Alpha αequals 0.05 is there enough evidence to support her claim?Assume that the population is approximately normally distributed.
A sample of 49 observations is taken from a normal population with a standard deviation of 10. The sample mean is 55.
A sample of 49 observations is taken from a normal population with a standard deviation of 10. The sample mean is 55. Determine the 99% confidence interval for the population mean. (Round your answers to 2 decimal places.) Confidence interval for the population mean is _______ and _______ .A research firm conducted a survey to determine the mean amount Americans spend on coffee during a week. They found the distribution of weekly spending followed the normal distribution with a population standard deviation...
The mean amount of money spent per week on gas by a sample of 25 drivers...
The mean amount of money spent per week on gas by a sample of 25 drivers was found to be $57.00 with a standard deviation of $2.36. Calculate the margin of error for a 90% confidence interval. *Assume that the population is approximately normal. Possible Answers: A: $0.81 B: $0.71 C: $1.19 D: $1.23
The owner of a coffee shop has found that the average amount spent by a sample of 25 customers is $8.60 with a sample s...
The owner of a coffee shop has found that the average amount spent by a sample of 25 customers is $8.60 with a sample standard deviation of $1.4. What are the lower and upper bounds of a 90% confidence interval for the population mean amount spent (in dollars) by customers? (6.32, 7.28) (6.34, 7.26) (8.12, 9.08) (9.50, 9.70)
Suppose a survey research firm selected a simple random sample of 300 people for the purposes...
Suppose a survey research firm selected a simple random sample of 300 people for the purposes of estimating their mean weekly income and found that the sample mean was $1,345.78 with a standard deviation of $257.90 Calculate the 90% confidence interval for the population mean.
A group of friends has gotten very competitive with their board game nights. They have found...
A group of friends has gotten very competitive with their board game nights. They have found that overall, they each have won an average of 18 games, with a population standard deviation of 6 games. If a sample of only 2 friends is selected at random from the group, select the expected mean and the standard deviation of the sampling distribution from the options below. Remember to round to the nearest whole number. Select all that apply: A.) σx¯=6 games...
1) A professor knows that in the past, the average amount of time spent studying the...
1) A professor knows that in the past, the average amount of time spent studying the night before the first exam was 140 minutes with a normal distribution and a standard deviation of 75.1. The professor finds that the average amount of time spent studying the night before the first exam for the current class of 40 students is 165 minutes. a) Please identify the following values from the above study description. The population mean (µ) equals ________________. The population...
in a recent survey of high school students, it was found that the amount of time...
in a recent survey of high school students, it was found that the amount of time spent on rading books per week, was normally distributed with a mean of 23 minutes. Assume the distribution of weekly reading time follows the normal distribution with a population standart deviation of 2 minutes. Suppose we select a sample of 11 high school students. A- What can we say about the shape of the distributiob of the sample mean time? ….. B- What is...
C is incorrect. Please show your work.
21. Suppose a research firm conducted a survey to determine the mean amount steady smokers spend on cigarettes during a week. A sample of 75 steady smokers revealed that the sample mean is $68. The population standard deviation is $13. What is the probability that a sample of 75 steady smokers spend between $65 and $72? A. 0.9518 B. 0.0028 C. 0.9544 D. 0.9733
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