Question

For the beam and loading shown, determine the maximum absolute values of bending moment. a = 6 m, b.= 8 m, F = 5 kN.m. AO Select one: a. M -7.66 kN.m max b. M = 15.13 (N.m C. M - 18.96 kN.m max d. M = 11.34 kN.m e. M 4.17 kN.m

Answer 1

solt The given team is. ко samply supported cheam. The guen beam is a Free body diagrams HA TVc am * zme In the question peelien Fusa Fusa UDL. But UDL. But its units are genen as know which as the units of moment, So, writs of t = kN/m. Reaction calculation : I Housental forces = 0 HA=0 a Vertical forces - 0 » VA+Nc z10 = (5x2) I Menents - Taking moments about C. I Mc=0 I Me=0= VAX 8 - 5x2* ? - VA= 1.25 KN. Vc = 10-1.25 = 8.75 KN.

Shear force calculation; We know that where the shear force becomany Bero, there the bending mement will be mariamm SE at A = 1.25 SE at B= 1.25 (Constant) SR at c= 1.25 - 5x2 = – 8.75 KN. In the span be, the SE becomay zero. 1.25 (2-x) From sunlar traurgly 1.25 8.75 az 2.0 -8.75 x= 0.25m From left side . The bending moment is mammum at 1.75m from right support or 6.25 m from left support i. Man BM = 8.75* 1.75 - 15x1.75 x( leiths) = 7.65625 kNom The manimum absolute benday mencent as +7.65625 kN-mn +7.66 kN-m.
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