Question

Review | Constants Periodic Table Solid carbon can react with gaseous water to form carbon monoxide gas and hydrogen gas. The equilibrium constant for the reaction at 700.0 K is 1.6x10-3Kp. Part A If a 1.55-L reaction vessel initially contains 120 torr of water at 700.0 K in contact with excess solid carbon, find the percent by mass of hydrogen gas of the gaseous reaction mixture at equilibrium. VO ALQ * 0 2 ? m H2 MHz +mco+mH2O Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining

Answer 1

Sol":- Given in o(s) + HO (9) = Co (9) + 403) (excess) - 3 - also Hence will c(s) is pure solid Kp = 106x10 s atm the activity coefficient (d) at took taken as "1" fact ton 2 Analysis: C(s) + 40(9) = COCG) + y (9) Ko=116X163 afrin +=o del 120 torr 0 0 tatea d=1 120-re x x torr tom for So, Kp = lcolg; • P409) = x 120-2 PARO (9) 1.6x103 = x² , taking approximation checking 120-2 as keq is very less approximation; 120»» 0.438 +17 1.6X6.2 x lofx 103 - Hence we can 1.92x10 = x² write 19.2x102 = x² 120-x 120 x = 4.38 x 10 = 0.438 forr ~120

so, Pozog otor CO(g) = 0,438 0.438 using : tor Lamm = 760 ton] = 0.0006 atm ter 0.000 6 atm Paco HO () 120 tour = (120 - 01439) torr = = 0.15 atm gas equation , using Ideal Co = Pcor n - Proly Ho- RT RT RT n = 0.0006 41155 0:0821 X 700 n ) co- = 6X10 X1155, n. = 0.16 x 1.55 010821 X 700 0:0821 X700 Mouse 0.16 xro", co = 0.16% 17%, no = 0,0043 (Mo) = 2 gyfrol (9.) = ao gol. Como a lo gryme | m muola) u 774x104 mm = 0.32x104 , Mors= 4.48 x 10 (9) gms gms gms Hence, mass % of the (9) is = mag x 100 %. 2 = 0.32 x 1024 X 100 (0.32 + 4.46 + 774) x64 mass% of (9) is = 0. 041%