Homework Answers
Pic is not clear. Please pardon . Repost if I have taken different value. Otherwise you can solve this question in following manner
hypothesis statements , given in option A is correct.
Actual Values:
39 21 15
23 26 11
25 33 16
Expected Values:
31.2201 28.7081 15.0718
24.9761 22.9665 12.0574
30.8038 28.3254 14.8708
Chi-Squared Values:
1.93872 2.06963 0.000341763
0.156345 0.400674 0.0927337
1.09351 0.771474 0.0857426
Chi-Square = 6.60917
Degrees of Freedom = 4
p = 0.15804
Here P value is greater than 0.05 hence we can not reject null hypothesis. It means that both variable are independent. option B is correct.
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#not sure if i got the first parts right but really not sure about last parts....
#not sure if i got the first parts right but really not sure about
last parts. thank you for any help!!!
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last parts. thank you for any help!!!
A genetic experiment involving peas yielded one sample of offspring consisting of 449 green peas and 162 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses...
Please help
After getting trounced by your little brother in a children's game, you suspect the die he gave you to roll may be unfair. To check, you roll it 60 times, recording the number of times each face appears. Do these results cast doubt on the die's fairness? Face 1 Count 11 8 5 Face 4 5 6 Full data set Count 6 7 23 2 3 a) If the die is fair, how many times would you expect...
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I am unable to figure this out. Please show some work if
possible. Thanks in advance!
The test statistic of z- -2.99 is obtained when testing the claim that p < 0.36. a. Using a significance level of α=0.01, find the critical value(s). b. Should we reject Ho or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table a....
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