Use a numerical solver and Euler's method to obtain a four-decimal approximation of the indicated value. First use
h = 0.1
and then use
h = 0.05.
y' = y − y2, y(0) = 0.3; y(0.5)
MATLAB Script:
close all
clear
clc
f = @(x,y) y - y^2; % Given ODE
x0 = 0; xf = 0.5; % Intervals of x
y0 = 0.3; % Initial condition
h1 = 0.1; % Step Size 1
y1 = euler(x0, y0, xf, h1, f);
fprintf('For h = 0.1, y(0.5) = %.4f\n', y1(end))
h2 = 0.05; % Step Size 2
y2 = euler(x0, y0, xf, h2, f);
fprintf('For h = 0.05, y(0.5) = %.4f\n', y2(end))
function y = euler(x0, y0, xf, h, f)
y(1) = y0;
x = x0:h:xf;
for i = 1:length(x)-1
f1 = f(x(i), y(i));
y(i+1) = y(i) + h*f1; % Euler's Update
end
end
Output:
For h = 0.1, y(0.5) = 0.4123
For h = 0.05, y(0.5) = 0.4132
Use a numerical solver and Euler's method to obtain a four-decimal approximation of the indicated value....
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