Find the absolute value of specific work input required my pumps 3 and 4 in J/kg
I will include all the data I have as I'm not sure what is relevant to determine this.
Pump1 at the reactor zone electrical power consumption: Ppump1 = 21 kW
Pump2 between condenser and steam generator electrical power consumption: Ppump2 = 781.1 kW
Power output from turbine: WT = 46,642.2 kW
Pressure drop across the condenser for the cooling water: ΔpCD = 24.1 kPa
Temperature rise in the condenser for the cooling water: ΔTCD = 13.5 oC
River water temperature: 6.5oC
The cool water basin temperature: 15.5 oC
Electric efficiency of the generator: ηelectric= 90.6 %
Cooling water pipe length for stage AB 45.1 m
Cooling water pipe length for stage BC 15.35 m
Cooling water pipe length for stage DE 15.35 m
Elevation difference between AB ΔZAB= 18.2 m
Elevation difference between BE ΔZBE= 5.6 m
Velocity at the surface of the cool water basin: CB = 0 m/s
Velocity at the exit of the warm water spray: Same as velocity in the pipe
Pump3 & Pump4 have an efficiency of: ηpump = 63 %
diameter of pipeline 0.472m
The specific enthalpy at the entry of the turbine = 2879.6 kJ/kg
The specific enthalpy at the exit of the turbine = 1918.5 kJ/kg
The specific enthalpy at the exit of the condenser = 242 kJ/kg
2.A. the mass flow rate of the steam in the secondary loop: ____48.53________ kg/s
2.B. the mass flow rate of the cooling water in the tertiary loop: _______1441.07_____ kg/s
For the pipe section AB:
. the mean velocity of the water: ______8.24______ m/s
.
. the Reynold's number: _____3067842.1_______
. The type of flow:
. The friction factor: _0.00369________
For the pipe section BE:
the mean velocity of the water: _____8.255_______ m/s
the Reynold's number: ___4084976.7_________
The friction factor: _0.00367________
We are asked to find:
The pump 3 is used to:
So, if we consider an open system with inlet occuring at B and exit occuring at E, and the entire pipe from BC through CD and DE as the control volume, then applying SFEE:
where
Total head loss = Head loss in the pipes due to friction + Pressure head loss in the condenser
Head loss in the pipes due to friction =
where
Pressure head loss in the condenser =
where
Total head loss = = H1 + H2 = 0.8313 + 2.457 = 3.2883 m
Total specific energy loss =
where
So,
[Negative sign indicates work done by the pump]
This is the ideal work. The actual work is:
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We will do the same process for pipe section AB:
where
Total head loss = Head loss in the pipes due to friction
Head loss in the pipes due to friction =
where
Total head loss = = H1 = 1.22 m
Total specific energy loss =
where
So,
[Negative sign indicates work done by the pump]
This is the ideal work. The actual work is:
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The work done by the pump 4 IS MUCH GREATER THAN the work done by pump 3. This is because, if we were to neglect the potential energy heads, the temperature of water is rising quite considerably, from 6.5 C (in the pond) to 15.5 C (in the cooling tower). This causes the work input to increase a lot, because water has a very high specific heat.
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