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not ho chi The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the
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Answer #1

Ans 1) Linear regression equation: \hat{y} = -243.6 + 10.2x ans,

Ans 2) put x = 48 in equation : y -243.6 + 10.2 x 48 = 246.0 pounds ans.

Ans b) The result is not very close to the actual weight of the bear.

Explanation: 246 \neq 218

Explanation:

Linear regression Coefficient:

b = \frac{\sum_{i=1}^{n}(x_{i}-\bar{x})(y_{i}-\bar{y})}{\sum_{i=1}^{n}(x_{i}-\bar{x})^2}

and

a=y-b.c

Mean = \bar{x} = \frac{58+49+...+57}{6} = 51.83

Mean = \bar{y} = \frac{355+266+...+348}{6} = 287.33

\sum_{i=1}^{6}(x_{i}-\bar{x})(y_{i}-\bar{y}) = (417.28+60.44+...+313.44) = 2282.33

\sum_{i=1}^{6}(x_{i}-\bar{x})^2 = (38.028+8.028+...+26.69) = 222.83

therefore,

b = \frac{2282.33}{222.83} = 10.2

a = 287.3 - 10.2\times 51.83 = -243.6

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