A 5μF capacitor is charged to 30 V and is then connected in series with a 10μH inductor and a 50Ω resistor. The initial current in the circuit will be
Correct answer is 0.600 A
Show all work
As clear from the diagram given below
Using KVL,
IR + L(dI/dt) = 30
But initially the current is minimum and hence dI/dt = 0 and hence
IR + L(0) = 30
IR = 30
I = 30/R
= 30/50
I = 0.600 A
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