You measure 41 turtles wroghrs and find they have a mean weight of 60 ounces. Assume the population standard deviation is 13.6 ounces. Based on this, construct a 95% confidence interval for the true population mean turtle weight.
Solution :
Given that,
Point estimate = sample mean = = 60
Population standard deviation = = 13.6
Sample size = n = 41
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (13.6 / 41)
= 4.2
At 95% confidence interval estimate of the population mean is,
- E < < + E
60 - 4.2 < < 60 + 4.2
55.8 < < 64.2
(55.8 , 64.2)
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