Question

At an assemb.y plant for light trucks, routine monitoring of the quality of weds yields the following data: The results are presented in the following table. Observed Values Number of Welds High Quality Low Quality Moderate Quality 191 Day Shift Evening Shift Night Shift 467 445 254 171 129 a) State the appropriate null hypothesis? b) Compute the table of expected values under the null hypothesis. c) Compute the value of the Chi-square statistics d) Find the P-value. What do you conclude?

Answer 1

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The null hypothesis is :

a. The kind of shift is not independent of quality of welds

b. The contingency table below provides the following information: the observed cell totals, (the expected cell totals) and [the chi-square statistic for each cell].

c. Chi Square statistics =

The chi-square statistic is 5.7604.

d. p-value

The p-value is .217767. The result is not significant at p < .05.