Please Help me with my homework problems.
here, let the initial resistance is R
R = p * L/A
L is the length and A is the area of cross section
Now, when the wire is cut in half
R = p * (L/2)/(2A) *
R = 1/4 * p * L/A
hence , the new resistance is 1/4 times the initial resistance
Please Help me with my homework problems. D FG Problem 6. A length of wire is...
Please draw pictures!!! 20. (II) A length of wire is cut in half and the two lengths are wrapped together side by side to make a thicker wire. How does the resistance of this new combination compare to the resistance of the original wire?
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