Calculate ΔSo in J/K for the following
reaction:
2Fe2O3(s) + 3C(s) → 4Fe(s) +
3CO2(g)
So(Fe2O3(s)) = 87.4 J/K/mol
So(C(s)) = 5.7 J/K/mol
So(Fe(s)) = 27.3 J/K/mol
So(CO2(g)) = 213.7 J/K/mol
2Fe2O3(s) + 3C(s) → 4Fe(s) + 3CO2(g)
ΔSo = ΔS products - ΔS reactants
= (4 x 27.3 + 3 x 213.7 ) - ( 2 x 87.4 + 3 x 5.7)
= 750.3 - 191.9
= 558.4 J / K
ΔSo = 558.4 J / K
Calculate ΔSo in J/K for the following reaction: 2Fe2O3(s) + 3C(s) → 4Fe(s) + 3CO2(g) So(Fe2O3(s))...
Calculate the enthalpy of reaction for the following reaction: 2Fe2O3(s) + 3C(s) → 4Fe(s) + 3CO2(g) ΔHfo(Fe2O3(s)) = -824.2 kJ/mol ΔHfo(C(s)) = ? ΔHfo(Fe(s)) = ? ΔHfo(CO2(g)) = -393.5 kJ/mol
Consider the following reaction. 2Fe2O3(s)+3C(s)−heat→−4Fe(s)+3CO2(g) Calculate the number of grams of Fe2O3 needed to react with 12.0 g C.
for the following equation: 2Fe2O3 + 3C = 4Fe +3CO2, determine the following: a) how many moles of Fe2O3 are needed to make 7.25 mole of Fe? b) how many moles of CO2 can be made from 100. g f Fe2O3? c) how many grams of Fe can be made from 16.78 g of carbon?
Question 17 Not yet answered Calculate the enthalpy of reaction for the following reaction: 2Fe2O3(s) + 3C(s) - 4Fe(s) + 3CO2(g) Marked out of 1.00 Flag question AHI°(Fe2O3(s)) = -824.2 kJ/mol AH(C(s)) = ? AH®(Fe(s)) = ? AH(CO2(g)) = 3935 kJ/mol Answer:
Which of the reactions are exothermic? 2Mg(s)+O2(g)⟶2MgO(s)+heat2Mg(s)+O2(g)⟶2MgO(s)+heat NH3(g)+HCl(g)⟶NH4Cl(s)+heatNH3(g)+HCl(g)⟶NH4Cl(s)+heat AgCl(s)+heat⟶Ag+(aq)+Cl−(aq)AgCl(s)+heat⟶Ag+(aq)+Cl−(aq) 2Fe2O3(s)+3C(s)+heat⟶4Fe(s)+3CO2(g)2Fe2O3(s)+3C(s)+heat⟶4Fe(s)+3CO2(g) C(graphite)+O2(g)⟶CO2(g)+heatC(graphite)+O2(g)⟶CO2(g)+heat CH4(g)+2O2(g)⟶CO2(g)+2H2O(l)+heat
2.Calculate the enthalpy of reaction for the following reaction: Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g) ΔHfo(Fe2O3(s)) = -824.2 kJ/mol ΔHfo(CO(g)) = -110.5 ΔHfo(Fe(s)) = ? ΔHfo(CO2(g)) = -393.5 kJ/mol
Determine the value of AG for the following reaction: Fe2O3 (s) + 3 H2(g) → 2 Fe(s) + 3 H2O(g) Fe2O3(s) H2(g) Fe(s) H2O(g) AHf (kJ/mol) -824.2 0 0 -241.8 Sº (J/K mol) 87.4 130.6 27.3 188.8
The reaction of iron ore with carbon follows the equation: 2Fe2O3 + 3C + 3C02 → 4Fe In a reaction, 500 g of Fe2O3 are mixed with 100 g of C. The actual yield of Fe is 5.0 g, what is the percent yield of iron? o 40% 0 60% 20% O 80 % 10 %
Iron reacts with oxygen at high temperatures to form iron(III) oxide. 4Fe(s)+3O2(g)⟶2Fe2O3(s) Suppose 14.2 g of iron (Fe) is reacted with 18.1 g of oxygen (O2). Select the limiting reagent. Fe2O3 O2O2 FeFe Calculate the theoretical yield of iron(III) oxide (Fe2O3Fe2O3). theoretical yield = The reaction produces 5.40 g of Fe2O3. What is the percent yield of the reaction? percent yield =
4. What is the limiting reactant, theoretical yield, and % yield of iron metal (in kg) if 76.0 kg of Fe2O3 reacts with 22.1 kg of carbon to produce 42.3 kg Fe according to the following reaction: 2Fe2O3(s) + 3C(s) 4Fe(s) + 3CO2(g) Limiting Reactant - Fezoz Mass of Fe₂O₂ = 760kg Mole of Fe₂O₃ =475 grud Mass of carbon 22.1kg Mole of carbon = 1841.7 mol Theor. Yield =53.12 kg % Yield = 79.7%