A baseball (m=145g) traveling 37 m/s moves a fielder's glove backward 22 cm when the ball is caught. pleas explain in detail. i want to understand.
m = 145 g = 0.145 kg = mass of baseball
Vi = initial speed = 37 m/s
Vf = final speed =0
d = distance moved while slowing down = 22 cm = 0.22 m
a = acceleration
Using the equation
Vf2 = Vi2 + 2 a d
02 = 372 + 2 a (0.22)
a = - 3111.36 m/s2
force is given as
F = ma = 0.145 x 3111.36
F = 451.15 N
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