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Roulette: In the game of ro winning. If the metal ball lan players $5. What is the expce much would you expect to lose? n th
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Answer #1

Answer: In the game of roulette, a player can place a $5 bet on the number 17 and have a 1/38 probability of winning. If the metal ball lands on 17, the player win $180. Otherwise, the casino takes the player's $5.

Solution:

P(winning) = 1/38

Profit on winning = $180

P(losing) = 1 - (1/38)

= 37/38

Loss on losing = $5

The expected value of game

= P(winning) * profit + [- P(losing) * loss]

= (1/38 * 180) - (37/38 * 5)

= $4.7368 - $4.8684

= - $0.1316

Therefore, the expected value of game to the player is -$0.13.

If you played the game 1000 times, expect to lose:

Expected loss = 1000 * 0.1316

= $131.6

Therefore, the player would expect to lose about $131.6

As per HOMEWORKLIB RULES only first question to be solved. Please repost the other question.

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