Answer: In the game of roulette, a player can place a $5 bet on the number 17 and have a 1/38 probability of winning. If the metal ball lands on 17, the player win $180. Otherwise, the casino takes the player's $5.
Solution:
P(winning) = 1/38
Profit on winning = $180
P(losing) = 1 - (1/38)
= 37/38
Loss on losing = $5
The expected value of game
= P(winning) * profit + [- P(losing) * loss]
= (1/38 * 180) - (37/38 * 5)
= $4.7368 - $4.8684
= - $0.1316
Therefore, the expected value of game to the player is -$0.13.
If you played the game 1000 times, expect to lose:
Expected loss = 1000 * 0.1316
= $131.6
Therefore, the player would expect to lose about $131.6
As per HOMEWORKLIB RULES only first question to be solved. Please repost the other question.
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