Question

Complete Analysis of a Refrigerator Goal Solve for the performance coefficient of a refrigerator using a five-step process the includes: 1. Making a state table. 2. Making a process table. 3. Calculating the totals for Work, Heat, and Internal-Energy-Change. 4. Identifying the heat input (cold reservoir) and output (hot reservoir). 5. Calculating the performance coefficient of the refrigerator. isothermal Problem Shown in the figure to the right is a cyclic process undergone by a refrigerator. Your refrigerator shall use 9.0 moles of helium gas (monatomic). During the process a->b, the volume increases by a factor of b 3.0. т, - 300 K P, = 100,000 Pa Refrigerator Cycle Solution (1) Fill in the State Table (all pressures in Pascals, all volumes in cubic meters, all temperatures in K). Volume Pressure Temperature 100000 a .2245 300 100000 .6734 900 2245 300000 900 Work Heat du 44890 112390 67500 >b (2) Fill in the Process Table (all entries in Joules). b- -73974.29 -73974.29 >c -67500 -67500 C- >a Work = -29084.29 (3) Find the Totals: -29084.29 Heat = Q-hot 44890 (4) Find the heat input (from "cold reservoir") and the heat output (to "hot reservoir"): Q-cold = -73974.29 (5) Find the performance coefficient of the refrigerator: Coefficient = 1.54

please help. I did most of it, I just need the ones that were marked incorrect. Thanks!

Answer 1

heat gained heat lost. Heat input Heat output Pab :Q-hat ।।२3१० ग Q-hat %3D 8-Cold. -73974.22 67500 -14774.29 J Q-Cold Peryormance Co-ficint, p Q-Cold =141474.29 29084.29 B=4.86