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(Weight: 10%) Show what happens in the figure below when the following statement executes: v2.pop_back); kw: : vector<int> vl num items = 5 current_capacity 10 int the data [0] [1] 2 4 [5] [6 7 8] [9] 2 4 kw: :vector<int> v2 numitems = 5 current_capacity-10 int+ the data -

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Answer #1

pop_back() method removes the last element from the vector and reduces the vector size by 1.

Here v1 and v2 points to same data, and v2.pop_back() removes the last element (i.e. 5) from vector. Thus that is also reflected in v1. So num_items in both v1 and v2 will be: 4 . The figure will be as follows:

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