Question

1) After balancing the following equation, what is the coefficient for oxygen? CpH6(g) + O2(g) →-CO(g) + __ H2O(g) A) 2 B)5 C)3 D) 4 2) After balancing the following equation, what is the coefficient for LiOH? 2) A) 1 B) 5 C)3 D) 2 E) 4 3) Lithium and nitrogen react to produce lithium nitride: 3) 6Li(s)+N2(8) - 2Li3N(s) How many moles of lithium nitride are produced when 0.450 mol of lithium react in this fashion? C) 0.225 A) 0.900 B) 0.150 D) 1.35 E) 0.0750 4) Consider the following reaction. How many moles of oxygen are required to produce 2.33 moles of 4) water? Assume that there is excess C3H7SH present C3H7SH(0)+602(g) -3 CO2(8)+S02(8)+4 H20(g) A) 2.33 moles O2 B) 3.50 moles O2 C) 4.14 moles O2 D) 6.21 moles O2 E) 1.55 moles O2

Answer 1

Equation balances by hit & trial method and mole mole relationship is used to solve above problem.

BalanCes the all asoms of dlifferent elements in Reactant, side as wel, Prodụ다 Sĩde, ' 2) Answer! :-( D)、2 The. CoeffiGnt of Loh is 2 LiN-(a) 6 mole 1 mole 0-YS0moic G3smole- mole. 2 mole. or s Poblem 6 mole Li I mole D.45o mole 2. LI2N 3 1 mole f mol e exceh 2.33 moles

Mole -mole. Relationship js Used to Solre abore Pooblem 4 mole Ho pydces bymole 02 mole 2.33 3435 moes 02 3.50 moles D2 2.33 mole 02