What is the coefficient of Bi3+ after balancing the following equation? Bi3+(aq) + Fe3+(aq) + H2O => BiO31- + Fe2+ + H+(aq)
a. |
1 |
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b. |
2 |
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c. |
3 |
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d. |
4 |
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e. |
None of these |
The coefficient of Bi+3 is 1 after balancing the equation completely hydrogens, oxygen atoms and the charge balancing on bothe sides.
Bi+3 + 2Fe+3 +6OH- ---------------------------> BiO3- + 2Fe+2 + 3H2O
oxidation half
Bi+3 + 6OH- ------------------> BiO3- + 3H2O + 2 e- ( oxidation state of Bi changes from +3 to +5)
reduction half
2 Fe+3 + 2e- ---------------------> 2Fe+2 ( oxidation state of Fe changes from +3 to +2)
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Bi+3 + 2Fe+3 +6OH- ---------------------------> BiO3- + 2Fe+2 + 3H2O
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option a is correct
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