Question

-/1 POINTS MENDSTAT15 4.1.021. 0/6 Submissions Used MY NOTES ASK YOUR TEACHER Consider the following experiment. A bowl contains four candies-red, brown, yellow, and green. Draw two candies at random, one for you to eat, and one for a friend. Use a tree diagram to find the simple events for the experiment. (Enter your answers as a comma-separated list. Enter each simple event in the format ( C of the Ith candy. Use R for red, B for brown, Y for yellow, and G for green.) C ) where is the color Need Help? Rendit Watch it Talk to a Tutor 10. -/1 POINTS MENDSTAT15 4.1.022. 0/6 Submissions Used MY NOTES ASK YOUR TEACHER Consider the following experiment. A coin is tossed three times and the upper face (head or tail) is recorded for each toss. is the Use a tree diagram to find the simple events for the experiment. (Enter your answers as a comma-separated list. Enter each simple event in the format (0,0% 0,) where outcome of the Ith toss. Use H for heads and for tails.) Need Help? Red T ube Tube ..

Answer 1

There are 4 candies in total out of which you are drawing only two randomly.
Thus , It is a case of event without replacement.

You have 4 choices : RED (R) , Brown (B), Yellow (Y), Green (G).
Now, When you draw a candy for yourself then, that particular candy is not available for your friend .
He will be left with 3 choices then .
The tree diagram for the experiment is as follows, where C1 is your candy , C2 is for your friend .

Case 1 : When your drawn candy is RED (R) , your friend is left with either Brown (B) or Yellow (Y) or Green (G) , represented as :
(R,B) (R,Y) (R,G)

Case 2 : When your drawn candy is BROWN (B) , your friend is left with either Red (R) or Yellow (Y) or Green (G) , represented as :
(B,R) (B,Y) (B,G)

Case 3 : When your drawn candy is YELLOW (Y) , your friend is left with either Red (R) or Brown (B) or Green (G) , represented as :
(Y,R) (Y,B) (Y,G)

Case 4 : When your drawn candy is GREEN (G) , your friend is left with either Red (R) or Brown (B) or Yellow(Y) , represented as :
(G,R) (G,B) (G,Y)

Thus , Total Outcomes are:

(R,B) (R,Y) (R,G)
(B,R) (B,Y) (B,G)
(Y,R) (Y,B) (Y,G)
(G,R) (G,B) (G,Y)

Rest all questions are also similar.