Question

Resources Give Up? Feedback Resume 7100 Question 1 of 12 > Attempt 3 0/100 An unsuspecting bird is coasting along in an easterly direction at 3.00 mph when a strong wind from the south imparts a constant acceleration of 0.500 m/s. If the wind's acceleration lasts for 2.90 s, find the magnitude r and direction 8 (measured counterclockwise from the easterly direction) of the bird's displacement over this time interval. Assume that the bird is originally travelling in the +x direction and that there are 1609 m in 1 mi. 00 0/100 0 28.4 10/100 0/100 Now, assume the same bird is moving along again at 3.00 mph in an easterly direction, but this time, the acceleration given by the wind is at a d = 35.0° angle to the original direction of motion, measured counterclockwise from the easterly direction. If the magnitude of the acceleration is 0.600 m/s", find the displacement vector i and the angle of the displacement , Enter the components of the vector, Fs and ry, and the angle. Assume the time interval is still 2.90 s. 300 Fari+r) 100 00/100

Answer 1

solmi. Time interval for wind How = 2.950c. 0-5 mts? thus 51:34 mise 1-382s distance covered in wind direction Swind = ett tat? L ē 540-5 X 8.92 2:1025 m NOW, distance travelled in east direction Seabr - Vt a 1134 x 2.9. - 2 3.886 m, vence V22.102512+ (3.88612 4.42 m Now, Os tant / 3.886 | 12-1025 Measured from east clock wipe - Else 28.1. dira în counter- | Time interval = 2.9 se 7.34 master 13 --- -- OC3A in 1. Bio sauce covered wind direction, Datoomis?

bu Page F. Swind bat? Obinte ¿ 05 X 06 x 2.92 1-34 ml see = 2.523 m Distance sorucam covered in east wind direction - Start Seest 2 vf a - 2.34 x 2.9 3.886 m, = | Now, rx = 3-886 + 2'523 cos (359) - 5.953_m ry 2 2.523 vin (85°) 2 1.45 m. | Hence, ma 5.953 î + Las ĝ This o tara lain ) = 18-69° any.